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Old December 5th, 2011, 01:00 PM   #25
Skippii
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Name: Skippii
Location: Richmond, Va
Join Date: Aug 2011

Motorcycle(s): 2007 Orange DRZ400-S, 2005 Ninja 250 & Custom Thundercunt Dirt Chopper

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Quote:
Originally Posted by dubojr1 View Post
Anyone know what resistor would be needed to do a high/low setup?

EDIT: Looks like this one will be it.

http://www.bikesax.com/Merchant2/merchant.mvc?
That link doesn't show a resistor.
The easiest way is to do a parallel/series switch, then you don't need a resistor, but it does make the "low" setting a good bit lower than otherwise
(25% of the high).

It all depends on how powerful the gloves are. If we assume 25 watt gloves,


12.5 volts from the bike times the current drawn = wattage of the gloves (25w), so the current drawn must be 2.
Ohms law tells us the 12.5V divided by 2 amps of current is a resistance of 6.25 ohms.
For 50% power (12.5w), we want only 1 amp to pass through the gloves at 12.5 volts.

With a 2.5 ohm resistor, the total circuit resistance is 8.8 ohms
This draws 1.42 amps
since the gloves make up 71.5% of the resistance, they dissipate 71.5% of the 17.6W total circuit power, so the gloves will run at ~12.7 watts, or half the power as without a resistor. The other 5 watts is wasted as heat in the resistor, so make sure your resistor is rated for at least 5 watts.

This is a pretty inefficient way of doing things. Using a 555 chip and a power mosfet would be much more efficient.

You could also just buy one of these for 23 cents, which would give simply run your gloves at 10 watts.
http://www.mouser.com/ProductDetail/...xYmnKIvA6xE%3d

Here's a good resistor for 44cents:
http://www.mouser.com/ProductDetail/...7fG%252b3Rs%3d
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